9k^2=17

Solution for 9k^2=17 equation:

9k^2=17

We move all terms to the left:

9k^2-(17)=0

a = 9; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·9·(-17)
Δ = 612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{612}=\sqrt{36*17}=\sqrt{36}*\sqrt{17}=6\sqrt{17}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{17}}{2*9}=\frac{0-6\sqrt{17}}{18}
=-\frac{6\sqrt{17}}{18}
=-\frac{\sqrt{17}}{3}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{17}}{2*9}=\frac{0+6\sqrt{17}}{18}
=\frac{6\sqrt{17}}{18}
=\frac{\sqrt{17}}{3}
$